Project Euler Problem 6 (PHP)

Share the joy
  •  
  •  
  •  
  •  
  •  
  •  
  •  
  •  

Problem 6

The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Script

Execution Time: 0.0013 seconds

$sum = 0;
$squareSum = 0;

for($x = 1; $x<=100; $x++) {
    $sum += $x;
    $squareSum += ($x*$x);
}
$diff = $squareSum-($sum*$sum);

echo abs($diff).PHP_EOL;

Share the joy
  •  
  •  
  •  
  •  
  •  
  •  
  •  
  •  
This entry was posted in PHP, Programming, Project Euler and tagged , , , . Bookmark the permalink.

Comments are closed.